x^2-x=6.5

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Solution for x^2-x=6.5 equation:



x^2-x=6.5
We move all terms to the left:
x^2-x-(6.5)=0
We add all the numbers together, and all the variables
x^2-1x-6.5=0
a = 1; b = -1; c = -6.5;
Δ = b2-4ac
Δ = -12-4·1·(-6.5)
Δ = 27
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{27}=\sqrt{9*3}=\sqrt{9}*\sqrt{3}=3\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3\sqrt{3}}{2*1}=\frac{1-3\sqrt{3}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3\sqrt{3}}{2*1}=\frac{1+3\sqrt{3}}{2} $

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